js和jquery中json对象合并的方法
本文发布于 12 年前, 内容可能已经过时或失效!
如果需要将下面的json对象合并：
```javascript
var a = {"a": "1", "b": "2"}
var b = {"c": "3", "d": "4", "e": "5"}
```
想得到结果：
```javascript
var c = {"a": "1", "b": "2", "c": "3", "d": "4", "e": "5"}
```
直接使用js的话，可以用一下方法：
```javascript
<script>
function extend(des, src, override){
if(src instanceof Array){
for(var i = 0, len = src.length; i < len; i++)
extend(des, src[i], override);
}
for( var i in src){
if(override || !(i in des)){
des[i] = src[i];
}
}
return des;
}
var a ={"a":"1","b":"2"}
var b ={"c":"3","d":"4","e":"5"}
var c = extend({}, [a,b]);
alert(c.a);
</script>
```
当然如果你加载了jquery,那就更方便了。可以使用$.extend()方法，该方法有两种模式;
`[jQuery.extend( target [, object1 ] [, objectN ] )]`
http://api.jquery.com/jQuery.extend/#jQuery-extend-target-object1-objectN
#将后面的对象合并到新的对象中{}
`[jQuery.extend( [deep ], target, object1 [, objectN ] )]`
http://api.jquery.com/jQuery.extend/#jQuery-extend-deep-target-object1-objectN
#将后面的对象合并到新的对象中{},如果深度deep为true则将递归合并成为新对象.
## 实例：
```javascript
<script type="text/javascript">
# 请记得先加载jquery
var a ={"a":"1","b":"2"}
var b ={"c":"3","d":"4","e":"5"}
var c = $.extend({}, a,b);
console.log(c);
</script>
```